#![no_std] #![no_main] #![feature(type_alias_impl_trait)] use defmt::info; use core::cmp::Ordering; use embassy_executor::Spawner; use embassy_nrf::{bind_interrupts, peripherals}; use embassy_nrf::pdm::{self, Config, OperationMode, Pdm, SamplerState, Frequency, Ratio}; use fixed::types::I7F1; use num_integer::Roots; use microfft::real::rfft_1024; use {defmt_rtt as _, panic_probe as _}; // Demonstrates both continuous sampling and scanning multiple channels driven by a PPI linked timer bind_interrupts!(struct Irqs { PDM => pdm::InterruptHandler; }); #[embassy_executor::main] async fn main(_p: Spawner) { let mut p = embassy_nrf::init(Default::default()); let mut config = Config::default(); // Pins are correct for the onboard microphone on the Feather nRF52840 Sense. config.frequency = Frequency::_1280K; // 16 kHz sample rate config.ratio = Ratio::RATIO80; config.operation_mode = OperationMode::Mono; config.gain_left = I7F1::from_bits(5); // 2.5 dB let mut pdm = Pdm::new(p.PDM, Irqs, &mut p.P0_00, &mut p.P0_01, config); let mut bufs = [[0; 1024]; 2]; pdm .run_task_sampler( &mut bufs, move |buf| { // NOTE: It is important that the time spent within this callback // does not exceed the time taken to acquire the 1500 samples we // have in this example, which would be 10us + 2us per // sample * 1500 = 18ms. You need to measure the time taken here // and set the sample buffer size accordingly. Exceeding this // time can lead to the peripheral re-writing the other buffer. let mean = (buf.iter().map(|v| i32::from(*v)).sum::() / buf.len() as i32) as i16; let (peak_freq_index, peak_mag) = fft_peak_freq(&buf); let peak_freq = peak_freq_index * 16000 / buf.len(); info!( "{} samples, min {=i16}, max {=i16}, mean {=i16}, AC RMS {=i16}, peak {} @ {} Hz", buf.len(), buf.iter().min().unwrap(), buf.iter().max().unwrap(), mean, ( buf.iter().map(|v| i32::from(*v - mean).pow(2)).fold(0i32, |a,b| a.saturating_add(b)) / buf.len() as i32).sqrt() as i16, peak_mag, peak_freq, ); SamplerState::Sampled }, ) .await.unwrap(); } fn fft_peak_freq(input: &[i16; 1024]) -> (usize, u32) { let mut f = [0f32; 1024]; for i in 0..input.len() { f[i] = (input[i] as f32) / 32768.0; } // N.B. rfft_1024 does the FFT in-place so result is actually also a reference to f. let result = rfft_1024(&mut f); result[0].im = 0.0; result .iter() .map(|c| c.norm_sqr()) .enumerate() .max_by(|(_, a), (_, b)| a.partial_cmp(b).unwrap_or(Ordering::Equal)) .map(|(i, v)| (i, ((v*32768.0) as u32).sqrt())) .unwrap() }